Ace the Certified in Public Health (CPH) Exam 2025 – Launch Your Health Hero Journey!

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What happens to the virus count in food left out for 4 hours at 85 degrees Fahrenheit?

Increases exponentially because viruses multiply rapidly under these conditions

Increases slowly because the food temperature is still not as high as body temperature

Can increase or remain the same depending on the acidity of the food

Does not change

The correct answer is based on the understanding of how viruses behave in food. Unlike bacteria, which can reproduce rapidly under suitable conditions, viruses do not multiply on their own in food items. They require a living host to replicate. When food is left out at 85 degrees Fahrenheit for 4 hours, the viral load can either remain unchanged or decrease, since exposure to such conditions over time does not promote viral reproduction. Instead, any viruses present may be inactivated or die off due to environmental factors like temperature and humidity, or they could remain stable without increasing in number.

The rationale for the other choices includes the understanding that while bacteria can thrive in warmer temperatures, especially those in the danger zone (between 40°F and 140°F), viruses do not share the same capacity for growth outside a host. Hence, an increase in the virus count does not occur simply due to time and temperature alone, which is why the assertion about exponential growth would be inaccurate. Additionally, while the acidity of food can affect the stability and infectiousness of some viruses, it does not change the fundamental aspect that viruses do not multiply in food.

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